-16x^2+100x+72=0

Solution for -16x^2+100x+72=0 equation:

-16x^2+100x+72=0

a = -16; b = 100; c = +72;
Δ = b2-4ac
Δ = 1002-4·(-16)·72
Δ = 14608
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{14608}=\sqrt{16*913}=\sqrt{16}*\sqrt{913}=4\sqrt{913}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(100)-4\sqrt{913}}{2*-16}=\frac{-100-4\sqrt{913}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(100)+4\sqrt{913}}{2*-16}=\frac{-100+4\sqrt{913}}{-32}
$